Linear probing: Fixed the previous fix

Now I understand what the original remark was intended to say :)

06-hash/hash.tex

@@ -779,6 +779,7 @@ By the previous lemma, one of the first 4 blocks of~$R$ is critical.
 
 Hence, the probability that run length lies between $2^{\ell+2}$ and $2^{\ell+3}$
 is bounded by the probability that one of the 12 blocks
+(chosen independently of the actual length of the run)
 is critical. By union bound and our estimate on the probability that a~block is critical,
 we get: