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index.js 6.04 KiB
/* Process inline math */
/*
Like markdown-it-simplemath, this is a stripped down, simplified version of:
https://github.com/runarberg/markdown-it-math
It differs in that it takes (a subset of) LaTeX as input and relies on KaTeX
for rendering output.
*/
/*jslint node: true */
'use strict';
var katex = require('katex');
// Test if potential opening or closing delimieter
// Assumes that there is a "$" at state.src[pos]
function isValidDelim(state, pos) {
var prevChar, nextChar,
max = state.posMax,
can_open = true,
can_close = true;
prevChar = pos > 0 ? state.src.charCodeAt(pos - 1) : -1;
nextChar = pos + 1 <= max ? state.src.charCodeAt(pos + 1) : -1;
// Check non-whitespace conditions for opening and closing, and
// check that closing delimeter isn't followed by a number
if (prevChar === 0x20/* " " */ || prevChar === 0x09/* \t */ ||
(nextChar >= 0x30/* "0" */ && nextChar <= 0x39/* "9" */)) {
can_close = false;
}
if (nextChar === 0x20/* " " */ || nextChar === 0x09/* \t */) {
can_open = false;
}
return {
can_open: can_open,
can_close: can_close
};
}
function math_inline(state, silent) {
var start, match, token, res, pos, esc_count;
if (state.src[state.pos] !== "$") { return false; }
res = isValidDelim(state, state.pos);
if (!res.can_open) {
if (!silent) { state.pending += "$"; }
state.pos += 1;
return true;
}
// First check for and bypass all properly escaped delimieters
// This loop will assume that the first leading backtick can not
// be the first character in state.src, which is known since
// we have found an opening delimieter already.
start = state.pos + 1;
match = start;
while ( (match = state.src.indexOf("$", match)) !== -1) {
// Found potential $, look for escapes, pos will point to
// first non escape when complete
pos = match - 1;
while (state.src[pos] === "\\") { pos -= 1; }
// Even number of escapes, potential closing delimiter found
if ( ((match - pos) % 2) == 1 ) { break; }
match += 1;
}